In Snowflake, we can get the data of the users and sessions along with the first session of all users of a particular day. To get that, we will utilise the “row_number()” Function. In this blog, we will learn to use the “row_number()” function and get the first session.
If we have tables that include the data about sessions and users and want to view first session of all the users for a specific day, we can use the “row_number()” function. Example for “row_number()” function:
select us.user_id1, us.session_id1, s.start_date1, s.end_date1, row_number() over (partition by user_id order by start_date1 desc) as row_number from user_sessions1 us left outer join sessions1 s on s.id1 = us.session_id1 Where to_varchar(start_date1, ‘dd-mm-yyyy’) = ‘06-02-2022’
This provides every Session ID of the day and its row number. As we only require the second session of the day, we only require a row that has row_number: 2. To get that, we have to utilise the common table expressions
with cte_sessions1 as ( select us.user_id1, us.session_id1, s.start_date1, s.end_date1, row_number() over(partition by user_id1 order by start_date1 desc) as row_number from user_sessions1 us left outer join sessions1 s on s.id1 = us.session_id where to_varchar(start_date1, ‘dd-mm-yyyy’) = ‘09-01-2022’ ) select * from cte_sessions1 where row_number = 2;
The “row_number()” function is helpful for getting the required data, users, and sessions. I hope this provides you with the essential information about the “row_number()” function.
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